6÷2(1+2)= ?

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scottishguy

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6÷2(1+2)= ?

Doing the rounds on loads of forums.

Do you get 1 or 9?
 
9

You evaluate the parentheses first then any powers then the multiplication and division then addition and subtraction

So you get (6 / 2) x (1 +2) = 3 x 3 = 9
 
1
BODMAS gives the order in which you do the calculations

Brackets - sort out what is inside the brackets first (obviously following the right order :) )
Orders - powers, square roots etc
Division, Multiplication can be done in any order
Addition, Subtraction can be done in any order
 
BODMAS gives the order in which you do the calculations

Brackets - sort out what is inside the brackets first (obviously following the right order :) )
Orders - powers, square roots etc
Division, Multiplication can be done in any order from left to right in the order of the sum)
Addition, Subtraction can be done in any order from left to right in the order of the sum


my answer is 9 due to the same method that islander says

saying "in any order" allows for problems such as this therefore i have ammended Suvv's post about bodmas, or bidmas or whatever the **** you call it!)

allow of people incorrectly say that bodmas stands for "brackets, orders, division, multiplication, addition and subtraction, when infact it should correctly be "brackets, orders, division AND multiplication, addition AND subtraction" because division and multiplication have the same 'priority' so you work left to right
 
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The answer's one.

I'd love to know how anyone is getting nine from six divided by six?
 
6 /2(1+2) = ? work out the brackets...... 1+2 = 3...........
6/2*3= ? then as / and * have the same priority work from left to right so first with the divide..... 6/2=3.....
3*3 = ? and then your left with the multiplication..... 3*3 = 9.......
=9

the initial reaction is to work out the brackets, then multiply them out with the 2, but this does not follow BODMAS correctly,

some reading here
http://www.mathsisfun.com/algebra/operations-order-calculator.html
http://www.bbc.co.uk/schools/ks3bitesize/maths/number/order_operation/revise1.shtml
 
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I don't think you can solve this without knowing if you multiply or divide what's produced either side of the bracket.
 
9 almost definitely.

You do the brackets first but in this case it doesn't really make any odds.

1+2=3
6/2=3

3*3 = 9
 
It should be 1.

(6/2)(1+2) = 9

6/2(1+2) = 1

You only multiply what is directly beside the bracket. If it's a bracket next to it then it's the whole sum. If not it's the adjacent number.
 
if you transpose the equation it gives you the answer...

6 / 2 (1+2) = 9 transposes to 6 / 2 = 9 / (1 + 2) which is correct

6 / 2 (1+2) = 1 transposes to 6 / 2 = 1 / (1 + 2) which isn't :/
 
(6/2)/(1+2) = 1

but that is not the same sum, a number sat against a bracket such as 2(1+2) mean that it is multiply what is in the bracket by that number. in isolation this would give 6, however in our sum we have to do the preceeding divide 6/2x3 before multiplying the contents of the bracket with the two so we get 3x3 = 9
 
Sorry Whitewash.. was trying to say that one side of the equation gives three. The bracket result gives three, but how do you decide if you multiply them or divide them. Is there a mathematical default?
 
Sorry Whitewash.. was trying to say that one side of the equation gives three. The bracket result gives three, but how do you decide if you multiply them or divide them. Is there a mathematical default?

2(x) means that you multiply the number by the contents of the bracket
 
but that is not the same sum, a number sat against a bracket such as 2(1+2) mean that it is multiply what is in the bracket by that number. in isolation this would give 6, however in our sum we have to do the preceeding divide 6/2x3 before multiplying the contents of the bracket with the two so we get 3x3 = 9

oops might have given a bad example :lol:

I was implying the answer was 9 from the OPs question.
 
Err what about this then, is the site wrong:

http://www.mathsisfun.com/algebra/operations-order-calculator.html

This is the actual sum at the start.

It depends how the sum is written and the sum at the top of your example is not written with brackets so is not a direct comparator.

The key here is the use of the proper divided sign which you can't replicate properly on these algebra websites.

If the sum were written as 6/2 written as a fraction next to (1+2) then the answer is 9.

When it is written as 6 (divided sign) 2(1+2) then the sequence rule of parenthesis, multiplication, division, addition, subtraction comes into play.

Therefore the sum is 6 divided by 2(3) with parenthesis resolved.

It then becomes 6 divided by 6 with multiplication completed.

Then the answer is 1 after division is applied.

A website algebra website can't see that subtlety as it can't recognise both symbols.
 
P.s if you transpose the equation:

6 divided by 2(3) =1 it becomes 6 = 1*2(3) which is 6 = 1*6 which is 6 = 6 and therefore is correct.
 
Without looking at the thread, I'd say 9....

BODMAS means it whittles down to 3(3), ie 3x3
 
9

Even with the explanations I still can't break that equation down to have 1 as the answer :shrug:
 
OOOOOhhhhhh nnnnnnooooooo !!!!!!!

Not this again. On one of the others forums I frequent this has already run to 76 pages of discussion!

:bang:
 
Oh, if anyone isn't sure then you can enter this into excel or any other spreadsheet...

=6/2*(1+2)
 
I got 9 working with the BODMAS theory (what I can remember of it) but have always been bad at maths so may be wrong :lol:
 
ziggy©;3631593 said:
Based on BODMAS

Code:
Brackets       - 6/2(1+2)
Multiplication - 6/2(3)
Multiplication - 6/2*3
Division       - 6/6

=1

I am corrected! Told you I was bad :help:
 
DemiLion said:
The answer's one.

I'd love to know how anyone is getting nine from six divided by six?

Where do you get the division Mark?
Surely it's:

1+2
multiplied by:
6 divided by 2

ie: 3 x 3

:shrug:
 
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